Subject: Re: [xsl] Sort/Ordering Problems From: "Benjamin Richard Woline" <valjean@xxxxxxxxxxx> Date: Wed, 20 Jul 2005 13:22:13 -0500 (CDT) |
Fantastic, it is beautiful in its simplicity. Someday I may have time to really figure out what you did. Thanks much. > > If you do this > <xsl:for-each select="//Entry"> > you get all entries from all levels, > > You want something like a stylesheet with (just) this template > > <xsl:template match="Entry"> > <xsl:copy> > <xsl:copy of select="@*"/> > <xsl:apply-templates select="Entry"> > <xsl:sort select="@importance" data-type="number" order="ascending"/> > </xsl:apply-templates> > </xsl:copy> > </xsl:template> > > David > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by Star. The > service is powered by MessageLabs. For more information on a proactive > anti-virus service working around the clock, around the globe, visit: > http://www.star.net.uk > ________________________________________________________________________
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