Subject: [xsl] Sorting values that contain spaces From: JBryant@xxxxxxxxx Date: Thu, 21 Jul 2005 11:56:39 -0500 |
Given input like this (a list of SQL table names): <tables> <table name="Claim"/> <table name="Claim Aggregate Queue"/> <table name="Claimant"/> <table name="Claim Association Fact"/> </tables> And XSL like this: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="tables"> <xsl:for-each select="table"> <xsl:sort select="@name"/> <xsl:value-of select="@name"/><xsl:if test="not(position() = last())"><xsl:text>, </xsl:text></xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> I get this: Claim, Claim Aggregate Queue, Claimant, Claim Association Fact I would like to get this: Claim, Claim Aggregate Queue, Claim Association Fact, Claimant How can I get that? I checked the FAQ and various archives of the list, but I didn't find anything on target. Thanks. Jay Bryant Bryant Communication Services (presently consulting at Synergistic Solution Technologies)
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