RE: [xsl] Can't save a node tree in a variable.

Subject: RE: [xsl] Can't save a node tree in a variable.
From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx>
Date: Mon, 25 Jul 2005 15:23:56 +0100
From: John Robb <john_ok@xxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Can't save a node tree in a variable.
Date: Mon, 25 Jul 2005 17:12:04 +0300

Can you please help me?I want to save the sorted tree in a variable.
Whats wrong with the following xsl:
<xsl:variable name="sorted">
		<xsl:apply-templates mode="copy" select="data/item"/>
	</xsl:variable>
	<xsl:template match="@*|node()">
		<xsl:copy>
			<xsl:apply-templates select="@*|node()" mode="copy">
				<xsl:sort select="@sector"/>
				<xsl:sort select="@subsector"/>
			</xsl:apply-templates>
		</xsl:copy>
	</xsl:template>

And then I want to perform smth. like this:$sorted/item/@sector.
How is it possible to realize such a thing?
    ---

Didn't Michael explain this one earlier? You need to use a node-set extension function unless you have the luxury of using XSLT 2.
For use in MSXML you will need to use ms:node-set($sorted) and declare


xmlns:ms="urn:schemas-microsoft-com:xslt"

in your stylesheet.

Joe


Joe


Current Thread