Subject: Re: AW: [xsl] xsl:key function help From: "Joris Gillis" <roac@xxxxxxxxxx> Date: Thu, 04 Aug 2005 09:40:01 +0200 |
That is OK so far because I can understand. Regarding the Muenchian method which is described on Jenis site I tried the following:
<?xml version='1.0' encoding='UTF-8'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:key name="Categories" match="Tip" use="@Topic" /> <xsl:output method="xml"/> <xsl:template match="/"> <xsl:apply-templates select="Tip[generate-id(.) = generate-id(key('Categories',@Topic)[1])]"/> </xsl:template>
<xsl:template match="Tip" > <xsl:for-each select="key('Categories', @Topic)"> <xsl:value-of select="@Subtopic"/> </xsl:for-each> </xsl:template>
The usage of the 'key()' function and the implementation of the Muenchian grouping is 100% correct. The problem is really much easier: You do not want <xsl:template match="/"> but instead: <xsl:template match="TipDatabase">
regards, -- Joris Gillis (http://users.telenet.be/root-jg/me.html) B+N N1N;N.N8N5N9N1 N:N1N9 ON? N;N,N4N9 ON,N=ON1 N2N3N1N/N=N?ON= N1OO ON,N=O B;
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