Subject: RE: [xsl] How to sort attribute? From: "Ross, Douglas" <DRoss@xxxxxxxxxx> Date: Sat, 13 Aug 2005 10:33:08 -0400 |
John, Since Michael Kay points out that attribute order is implementation dependent and not quaranteed, you might consider transforming your attributes into elements, where element order is quaranteed to be maintained in document order. You could change Mukul's stylesheet slightly: <xsl:template match="x"> <x> <xsl:for-each select="@*"> <xsl:sort select="name()"/> <!-- change this to element tag: <xsl:attribute name="{name()}"><xsl:value-of select="."/></xsl:attribute> --> <xsl:element name="{name()}"><xsl:value-of select="string(.)"/></xsl:element> </xsl:for-each> </x> </xsl:template> Douglas Ross Senior Software Engineer, Advanced Development Kronos www.kronos.com Improving the Performance of People and Business(tm) by making software Smaller, Faster, Sharper, Easier -----Original Message----- From: Mukul Gandhi [mailto:gandhi.mukul@xxxxxxxxx] Sent: Saturday, August 13, 2005 5:33 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] How to sort attribute? Hi John, This could be the use-case for the problem you are trying to solve. XML file - <root> <x a="1" d="2" c="4" /> </root> XSLT file - <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes" /> <xsl:template match="/root"> <xsl:apply-templates select="x" /> </xsl:template> <xsl:template match="x"> <x> <xsl:for-each select="@*"> <xsl:sort select="name()"/> <xsl:attribute name="{name()}"><xsl:value-of select="." /></xsl:attribute> </xsl:for-each> </x> </xsl:template> </xsl:stylesheet> Regards, Mukul On 8/13/05, John Li <johnli121@xxxxxxx> wrote: > Hi, > > When exporting one node and its attribute, I want to sort its attributes > lexicographic. I try it as below but always fail. Anyone could help? > > <xsl:for-each select="@*"> > <xsl:sort select="name()"/> > <xsl:copy/> > </xsl:for-each> > > Thanks, > John
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