Subject: Re: [xsl] Problem with Sum function From: Jon Gorman <jonathan.gorman@xxxxxxxxx> Date: Mon, 22 Aug 2005 11:09:24 -0500 |
On 8/22/05, Meena Nanjundeswar <meenasargur@xxxxxxxxx> wrote: > Hi: > > My xml file looks like this: > > <node1> > <childnode1a> > <childnode11a> > <value></value> > </childnode11a> > </childnode1a> > </node1> > > There can be any number of <childnode11a> elements containing <value>. > Now, I am trying to compute the sum(value). Instead of giving me a > total sum of all the rows, it display the values individually. Without seeing your stylesheet I can't but help guessing here, do you actually have a working sum statement? One possibility is that your templates are set up wrong so that just the built in rules are being used. Of course, there is the other where you have the template set up at the wrong level For example, say I had the xml doc as follows: <node1> <childnode1a> <childnode11a> <value>12</value> <childnode11a> <value>22</value> </childnode11a> </childnode1a> </node1> And if I have a stylesheet like so... <xsl:template match="childnode11a"> <xsl:value-of select="sub(value)" /> </xsl:template> it will always give back the individual values because the scope is wrong for the results you want. You're essentially asking it for the sum of all the value elements, which there will be only one of. Try something more like the following <xsl:template match="childnode1a"> <xsl:value-of select="sum(childnode11a/value)" /> </xsl:template> Without actually seeing your stylesheet I can only guess so much, but sum should be pretty straightforward. Jon Gorman
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