RE: [xsl] Moving an element to a new location in the Result-tree

["Christopher R. Maden" <crism@xxxxxxxxx>]

Jim Graves wrote:
> Good ideas! More details to get closer to a solution. It's copying and
> maintaining the tree as it is, yet still not 'moving' (figuratively, not
> literally, since it's a new tree) the elements to the new location in
> the new (result) tree. I think I see your logic, but I'm still missing a
> crucial insight. Can you pinpoint what it is -- to see the result
> desired, below?

Your transformation is pretty good, but its output isnt well-formed.

> <xsl:template match="Transfer">
>     <xsl:apply-templates select="Person"/>
> </xsl:template>

That template causes the Transfer element to disappear; only its content
is output.

> <xsl:template match="Person">
>      <xsl:apply-templates select="*[not(self::OTHER_NAME)]"/>
>      <xsl:apply-templates select="OTHER_NAME"/>
> </xsl:template>

Similarly, this processes the contents of Person, but doesnt output a
Person element itself.  Note this in my sample transform:

<xsl:template match="document1">
  <document222>
    <xsl:apply-templates select="*[not(self::b1)]"/>
    <xsl:apply-templates select="b1"/>
  </document222>
</xsl:template>

The template for document1 creates a document222 element, and processes
its own children inside that result element.  You need something more like

<xsl:template match="Person">
  <xsl:copy>
     <xsl:apply-templates select="*[not(self::OTHER_NAME)]"/>
     <xsl:apply-templates select="OTHER_NAME"/>
  </xsl:copy>
</xsl:template>

~Chris
-- 
Christopher R. Maden, Principal Consultant, crism consulting
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