Subject: RE: [xsl] Get value from update.xml and stored in source.xml(update source.xml) From: "Shailesh" <shailesh@xxxxxxxxxxxx> Date: Wed, 8 Sep 2004 14:49:43 +0530 |
Hi, Using below xsl the output is like: <?xml version="1.0" encoding="utf-8"?> <test> <chapter> <test1 id="0000001"> </test1> </chapter> </test> <test2> element is missing in source.xml which should be <test2>ABCD</test2>. -- Shailesh -----Original Message----- From: Joris Gillis [mailto:roac@xxxxxxxxxx] Sent: Thursday, September 08, 2005 2:26 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Get value from update.xml and stored in source.xml(update source.xml) Hi, Tempore 10:39:52, die 09/08/2004 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Shailesh <shailesh@xxxxxxxxxxxx>: > > Using xslt 1.0 I have to extract the value of <test2> which is in > <test1 id="0000001"> of update.xml and put it in <test2> which is in > <test1 id="0000001"> of source.xml. > > This should updates the <test2> of source.xml without any other changes. Try applying the following stylesheet to 'source.xml'. <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:output method="xml" /> <xsl:variable name="update" select="document('update.xml')"/> <xsl:key name="id" match="*" use="@id"/> <xsl:template match="*[@id]"> <xsl:variable name="id" select="@id"/> <xsl:copy> <xsl:apply-templates select="@*" /> <xsl:for-each select="$update"> <xsl:copy-of select="key('id',$id)/*"/> </xsl:for-each> </xsl:copy> </xsl:template> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*" /> </xsl:copy> </xsl:template> </xsl:stylesheet> -- Joris Gillis (http://users.telenet.be/root-jg/me.html) Deserta faciunt et innovationem appelant
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