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Subject: RE: [xsl] Is it possible to modify the source-tree? From: "Agnisys Technology \(P\) Ltd." <agnisys@xxxxxxxxx> Date: Tue, 13 Sep 2005 12:24:44 -0700 (PDT) |
Appreciate the responses. I'm using 2.0 so I'll ignore xx:node-set().
I'm still a little fuzzy, since I can't get the node to "stich" into the variable tree. Once
again,
Input is :
<a>
<b offset="5">
<reg>reg_1</reg>
<reg>reg_2</reg>
<reg href="REGDEF1"></reg>
<reg>reg_3</reg>
</b>
<regdef name="REGDEF1">
<reg>reg_10</reg>
<reg>reg_20</reg>
</regdef>
</a>
XSLT is :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="reg[@href]">
<xsl:variable name="reg_href">
<xsl:copy-of select="//regdef[@name=current()/@href]"/>
</xsl:variable>
<xsl:apply-templates select="$reg_href/*"/>
</xsl:template>
<xsl:template match="regdef"/>
<xsl:template match="reg">
<br/>Register : <xsl:value-of select="."/>
Offset = <xsl:value-of select="../@offset"/>
Prev-Sibling count = <xsl:value-of select="count(preceding-sibling::reg)"/>
</xsl:template>
</xsl:stylesheet>
Output is :
Register : reg_1 Offset = 5 Prev-Sibling count = 0
Register : reg_2 Offset = 5 Prev-Sibling count = 1
Register : reg_3 Offset = 5 Prev-Sibling count = 3
I want the output to say:
Register : reg_1 Offset = 5 Prev-Sibling count = 0
Register : reg_2 Offset = 5 Prev-Sibling count = 1
Register : reg_10 Offset = 5 Prev-Sibling count = 2
Register : reg_20 Offset = 5 Prev-Sibling count = 3
Register : reg_3 Offset = 5 Prev-Sibling count = 4
Thanks,
Anupam.
P.S. Jay, this is similar to the problem you helped me solve couple of weeks ago, but the
difference here is the need to acccess the parent attributes and sibling information.
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