Re: [xsl] can't get xsl:sort to work

["Joris Gillis" <roac@xxxxxxxxxx>]

Tempore 12:58:08, die 09/19/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit UlyLee <ulyleeka@xxxxxxxxx>:

> <xsl:for-each select="//complexarticle |
> //simplearticle | //dummyarticle">
> <xsl:sort select="@entry">
> <tr valign="top">
> <td><xsl:value-of select="@id"/></td>
> <td><xsl:value-of select="@entry"/></td>
> <td><xsl:variable name="x" select="count(.//xref)"/>
> <xsl:for-each select=".//xref">
> <xsl:value-of select="."/>
> <xsl:if test="position() &lt; $x">
> <br/>
> </xsl:if>
> </xsl:for-each>
> </td>
> </tr>
> </xsl:sort>
> </xsl:for-each>
>
> but when i run the transformation (i'm using
> xmlspy) i get and error "Expected select attribute or
> non empty content not both" but i have a select
> attribute.

The error message says it all.
You need:
<xsl:sort select="@entry"/>
you don't have to encapsulate the whole loop with this element;-)

regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
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