Subject: Re: [xsl] Strict sequential identity rule? From: andrew welch <andrew.j.welch@xxxxxxxxx> Date: Wed, 21 Sep 2005 15:54:05 +0100 |
On 9/21/05, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > Hi, > I think that trying to answer the following question can be interesting and > useful for the members of our community. > > Is the following statement true or false: > > "The transformation below is an identity transformation": > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output omit-xml-declaration="yes"/> > <xsl:template match="@* | node()"> > <xsl:copy> > <xsl:apply-templates select="@*"/> > <xsl:apply-templates select="node()[1]"/> > </xsl:copy> > <xsl:apply-templates select="following-sibling::node()[1]"/> > </xsl:template> > </xsl:stylesheet> On 9/21/05, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > Hi, > I think that trying to answer the following question can be interesting and > useful for the members of our community. > > Is the following statement true or false: > > "The transformation below is an identity transformation": > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output omit-xml-declaration="yes"/> > <xsl:template match="@* | node()"> > <xsl:copy> > <xsl:apply-templates select="@*"/> > <xsl:apply-templates select="node()[1]"/> > </xsl:copy> > <xsl:apply-templates select="following-sibling::node()[1]"/> > </xsl:template> > </xsl:stylesheet> I would say "yes" as it walks the tree in exactly the same way as the standard identity transform. The only difference here that I can see is that a no-op template would stop all output on the following axis, instead of the descendant axis, but I think that's just something to be aware of and not enough to say this isn't an identity transform. I hope this isn't going to be an anti-climax Dimitre...
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