Subject: [xsl] apply-templates with-param failed From: Xiaocun Xu <xiaocunxu@xxxxxxxxx> Date: Mon, 26 Sep 2005 18:08:06 -0700 (PDT) |
Hi, I am working on splitting a FindBugs result XML into multiple XMLs by finding keywords in Class/@classname. Keywords for all functional areas are defined in FunctionalAreaDef.xml: <Application> <FunctionalArea name="message"> <Keywords> <Keyword>notification</Keyword> <Keyword>message</Keyword> </Keywords> </FunctionalArea> ... </Application> I use the following XSL to read FunctionalAreaDef.xml, loop through each FunctionalArea element, create an output file using the FunctioalArea/@name and pass Keywords to BugCollection element(in the source FindBugs XML): <xsl:variable name="vFunctionalArea" select="document('FunctionalAreaDef.xml')"/> <xsl:template match="/"> <xsl:for-each select="$vFunctionalArea/Application/FunctionalArea"> <xsl:call-template name="splitByFunctionalAreas"> <xsl:with-param name="pFunctionalAreaDef" select="."/> </xsl:call-template> </xsl:for-each> </xsl:template> <xsl:template name="splitByFunctionalAreas"> <xsl:param name="pFunctionalAreaDef" select="."/> <xsl:variable name="vFileName" select="$pFunctionalAreaDef/@name"/> <xsl:result-document href="{$vFileName}_bugs.xml"> <xsl:apply-templates select="BugCollection"> <xsl:with-param name="pKeywords" select="$pFunctionalAreaDef/Keywords"/> </xsl:apply-templates> </xsl:result-document> </xsl:template> <xsl:template match="BugCollection"> <xsl:param name="pKeywords" select="."/> <xsl:value-of select="$pKeywords"/> ... Somehow the BugCollection template did not get evoked as <xsl:value-of select="$pKeywords"/> seems not evaluated (the output file is empty with just a XML header). I used matching mode as well, still no luck. Any suggestion on what have I done wrong would be much appreciated. thanks, Xiaocun __________________________________ Yahoo! Mail - PC Magazine Editors' Choice 2005 http://mail.yahoo.com
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