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Subject: [xsl] apply-templates with-param failed From: Xiaocun Xu <xiaocunxu@xxxxxxxxx> Date: Mon, 26 Sep 2005 18:08:06 -0700 (PDT) |
Hi,
I am working on splitting a FindBugs result XML into
multiple XMLs by finding keywords in Class/@classname.
Keywords for all functional areas are defined in
FunctionalAreaDef.xml:
<Application>
<FunctionalArea name="message">
<Keywords>
<Keyword>notification</Keyword>
<Keyword>message</Keyword>
</Keywords>
</FunctionalArea> ...
</Application>
I use the following XSL to read FunctionalAreaDef.xml,
loop through each FunctionalArea element, create an
output file using the FunctioalArea/@name and pass
Keywords to BugCollection element(in the source
FindBugs XML):
<xsl:variable name="vFunctionalArea"
select="document('FunctionalAreaDef.xml')"/>
<xsl:template match="/">
<xsl:for-each
select="$vFunctionalArea/Application/FunctionalArea">
<xsl:call-template name="splitByFunctionalAreas">
<xsl:with-param name="pFunctionalAreaDef"
select="."/>
</xsl:call-template>
</xsl:for-each>
</xsl:template>
<xsl:template name="splitByFunctionalAreas">
<xsl:param name="pFunctionalAreaDef" select="."/>
<xsl:variable name="vFileName"
select="$pFunctionalAreaDef/@name"/>
<xsl:result-document href="{$vFileName}_bugs.xml">
<xsl:apply-templates select="BugCollection">
<xsl:with-param name="pKeywords"
select="$pFunctionalAreaDef/Keywords"/>
</xsl:apply-templates>
</xsl:result-document>
</xsl:template>
<xsl:template match="BugCollection">
<xsl:param name="pKeywords" select="."/>
<xsl:value-of select="$pKeywords"/>
...
Somehow the BugCollection template did not get evoked
as <xsl:value-of select="$pKeywords"/> seems not
evaluated (the output file is empty with just a XML
header). I used matching mode as well, still no luck.
Any suggestion on what have I done wrong would be
much appreciated.
thanks,
Xiaocun
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