[xsl] Namespace on output node but not not in source

[António Mota <amsmota@xxxxxxxxx>]

Hi:

I have a xsl with a namespace declared

<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
	version="1.0"
	xmlns:xs="http://www.w3.org/2001/XMLSchema";>

so i can make some lookups on a xsd file

 <xsl:variable name="tipo"
select="$schema/xs:schema/xs:element[@name=$nome]/@type"/>

and that's all i do, i don't copy any node from $schema to the output tree.

However, this

        <xsl:template match="/">
                <table>
                        <xsl:apply-templates
select="(//Menu)[position()=$pos]"/>
                </table>
        </xsl:template>

produces a

<table xmlns:xs="http://www.w3.org/2001/XMLSchema";>
     <...>
</table>

and i don't understand why, and i don't want it there.

I add a exclude-result-prefixes="xs" but it seems it makes no diference.

Why is this?


Thanks.