Re: [xsl] xsl:key only checks first child, need to check all

[Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx>]

Hi Patrick,

> Which obviously would cause the problem I described. But that '[1]' was left
over from me debugging. Sorry about that. It doesn't really matter whether
it's there or not - I get the same results. So obviously [1] is the default
when no explicit expression is given. The problem is that I can't figure out
how to select all, something like [*].

Obviously [1] is not the default in general.

What you get is a nodeset containing all contains elements in the
given structure.
When you use the concat function, you get a string as an output.
Because of this, the nodeset is converted to a string using the rules
for this - meaning that you get the string value of the first element
in the nodeset.

Ragulf Pickaxe :-)