Subject: Re: [xsl] how to convert from list to grid ? From: David Carlisle <davidc@xxxxxxxxx> Date: Sun, 30 Oct 2005 23:51:53 GMT |
something like the following (untested) <xsl:template match="list"> <xsl:variable name="items" select="item"/> <table> <xsl:for-each select="$items[postion()<9]"> <xsl:variable name="y" select="position()"/> <tr> <xsl:for-each select="$items[postion()<9]"> <xsl:variable name="x" select="position()"/> <td><xsl:variable name="c" select="count($items[@x=$x][@y=$y])"/> <xsl:choose> <xsl:when test="$c=0">& # 1 6 0 ;</xsl:when> <xsl:otherwise><xsl:value-of select="$c"/></xsl:when> </xsl:choose> </td> </xsl:fdor-each> </tr> </xsl:for-each> </table> ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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RE: [xsl] how to convert from list , Michael Kay | Thread | [xsl] Indented HTML Lists > Multipl, Gogo Estragon |
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