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Subject: [xsl] Need help figuring out how to use exslt in stylesheet From: "Karr, David" <david.karr@xxxxxxxx> Date: Mon, 31 Oct 2005 15:45:09 -0800 |
I'm sure something I'm doing is completely misguided, but I'm still
experimenting here.
I'm trying to figure out how to have a stylesheet use the EXSLT library.
I'm also doing this inside Stylus Studio, which might complicate things.
I copied the entire exslt tree to the directory where I have my
stylesheet (probably overkill). I have an "xsl:import" for
"exslt/str/str.xsl". I have a root template that calls a sub-template,
passing a parameter. The sub-template tries to call "str:tokenize" and
put the result into a variable.
When I try to run the test on my sample data, I get an error:
-------
TransformerException: misplaced literal result in a func:function
container.
URL: file:.../exslt/str/functions/tokenize/str.tokenize.function.xsl
Line: 40
Col: 17
-------
Line 40 is the end tag of the "func:function" element defining
"str:tokenize".
I have the processor set to xalan-j 2.5.2.
My xslt is just this:
--------------------
<?xml version='1.0' ?>
<xsl:stylesheet version="1.0"
xmlns:str="http://exslt.org/str"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
extension-element-prefixes="str">
<xsl:import href="exslt/str/str.xsl"/>
<xsl:template match="/">
<addressData>
<complexAddress>
<xsl:call-template
name="extractAddress">
<xsl:with-param
name="simpleAddress" select="addressData/simpleAddress"/>
</xsl:call-template>
</complexAddress>
</addressData>
</xsl:template>
<xsl:template name="extractAddress">
<xsl:param name="simpleAddress"/>
<xsl:variable name="tokens"
select="str:tokenize($simpleAddress)"/>
<streetAddress>$tokens[0]</streetAddress>
<city>$tokens[1]</city>
<state>$tokens[2]</state>
<zip>$tokens[3]</zip>
</xsl:template>
</xsl:stylesheet>
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