Re: [xsl] Recursive substitution

[David Carlisle <davidc@xxxxxxxxx>]

> Output Expected XML:

The code I supplied last time gives that output on your new input file.

The only difference is that you have changed from wanting just the text
of the name attribute to a copy of the node, so change

Register: <xsl:value-of select="@name"/>

to

<xsl:copy-of select="."/>



<xsl:stylesheet version="2.0"
              xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:key name="r" match="define" use="@name"/>

<xsl:template match="x">
 <xsl:apply-templates select="block"/>
</xsl:template>

<xsl:template match="reg">
<xsl:copy-of select="."/>
</xsl:template>

<xsl:template match="ref">
 <xsl:apply-templates select="key('r',@name)"/>
</xsl:template>

</xsl:stylesheet>


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