Subject: [xsl] simple xsl:processing-instruction question From: "Aidan Hamwood" <parts_of_a_shoelace@xxxxxxxxxxx> Date: Tue, 08 Nov 2005 21:45:27 +0800 |
MSXML Installed MSXML2 Installed MSXML2 v2.6 I[g[V T[o[MIuWFNgp l,E+\9qB MSXML2 v3.0 Installed MSXML2 v4.0 Installed MSXML2 v5.0 I[g[V T[o[MIuWFNgp l,E+\9qB MSXML2 v6.0 I[g[V T[o[MIuWFNgp l,E+\9qB Mode Replace V3
<?xml version='1.0'?> <?xml-stylesheet type="text/xsl" href="pi.xsl" ?> <customers> <customer> <name>James Smith</name> <address>123 Elm St.</address> <phone>(123) 456-7890</phone> </customer> <customer> <name>Amy Jones</name> <address>456 Oak Ave.</address> <phone>(156) 789-0123</phone> </customer> </customers>
<?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method='xml' version='1.0'/> <xsl:template match="/"> <xsl:pi name="xml-stylesheet"> <xsl:text>type="text/xsl" href="styles.xsl"</xsl:text> </xsl:pi> <xsl:apply-templates /> </xsl:template>
<xsl:template match="@* | *"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template></xsl:stylesheet>
<?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method='xml' version='1.0'/> <xsl:template match="/"> <h1>hello</h1> </xsl:template>
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