Subject: Re: [xsl] Grouping / unique list with just XPath From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 17 Nov 2005 23:05:34 GMT |
> The problem is that I don't know the schema of the incoming files but > they're channeled through a recursive single template, so fiddling > around with keys to capture something that I currently trap in > <xsl:choose /> contraptions seem a bit tricky, I don't really understand why you can't use keys. You indicated you could use the another suggested method > select="$variable/member[@ref-id!=preceding-sibling::member/@ref-id]" > This will catch the first ref-id of each value. You need to know exactly the same information to use this method, the element names member and the attribute name ref-id, and one form can be mechanically converted to the other: <xsl:key name="m" name="match" use="@ref-id"/> ... <xsl:for-each select="$variable/member[generate-id()=generate-id(key('m',@ref-id))]"> well that selects the first member with each id, rather than just testing for first sibling, you can add the idof the parent if you need that. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Grouping / unique list wi, Alexander Johannesen | Thread | Re: [xsl] Grouping / unique list wi, Alexander Johannesen |
[xsl] Supposed to post XML variable, Bruso, John | Date | Re: [xsl] Grouping / unique list wi, Alexander Johannesen |
Month |