Re: [xsl] Grouping

Subject: Re: [xsl] Grouping
From: omprakash.v@xxxxxxxxxxxxx
Date: Wed, 7 Dec 2005 15:04:16 +0530
Hi Ragulf,
           I  take back my previous post as I don't see where I am wrong.
The muenchian grouping is not required for the answers and only for the
questions that too only if the OP is prticular about it.

Otherwise, my code should work fine.


                      Ragulf Pickaxe                                                                                                   
                      <ragulf.pickaxe@         To:      xsl-list@xxxxxxxxxxxxxxxxxxxxxx                                                
            >               cc:      (bcc: omprakash.v/Polaris)                                                     
                                               Subject: Re: [xsl] Grouping                                                             
                      12/07/2005 02:55                                                                                                 
                      Please respond                                                                                                   
                      to xsl-list                                                                                                      

Hi prakash,

>  <xsl:output method="xml"/>
> <xsl:key name="rec" match="row" use="question_id"/>
> <xsl:template match="/recordset">
> <xsl:for-each select="row">
> <xsl:if test="generate-id(.) = generate-id(key('rec', question_id))">
> <xsl:text>
> </xsl:text>
> Answers for question <xsl:value-of select="question_id"/>
> </xsl:if>
> <xsl:text>
> </xsl:text>
> <xsl:value-of select="key('rec', question_id)/answer"/>
> <xsl:text>
> </xsl:text>
> </xsl:for-each>
>  </xsl:template>

Will you not have a problem here, if question_id are not ordered?
As I read it, you go through all row elements. You check if the value
of question_id is the first of its kind, and if it is, you write the
Answers to question...
Then you proceed to write the value of the answer element.
As I see it, <xsl:value-of select="key('rec', question_id)/answer"/>
is the same as <xsl:value-of select="answer"/>, and as you have not
made sure of the value of question_id in your for-each, then this can
be wrong.

If I have not understood this correctly, please correct me.

A key approach, I would use (modifying your template):

<xsl:for-each select="row[generate-id(.) = generate-id(key('rec',
Answers for question <xsl:value-of select="question_id"/>
<xsl:for-each select="key('rec', question_id)/answer">
<xsl:value-of select="."/>

This one will work no matter the order of question_id's.

Ragulf Pickaxe :-)

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