Subject: [xsl] Using a template's (HTML) output as with-param? From: "Talley, Brooks" <brooks@xxxxxxxx> Date: Thu, 8 Dec 2005 17:10:54 -0800 |
I'm pulling my hair out. I've got an xslt template in an include file that's designed to return a complete <a> tag, with href and inner text and all (many xslt templates use this include so I don't have to hardcode url's in each template). So far, so good. However, now I need to use that template's output as a parameter to another template that's designed to put some formatting on a table heading. Everything works great... Except my <a> tag disappears when I use it this way. In fact, *any* html markup disappears, as show below: URL template: <xsl:template name="HrefTest"> <xsl:text><h3>test</h3></xsl:text> </xsl:template> Caption template: <xsl:template name="TableHeader"> <xsl:param name="caption1" /> <xsl:param name="caption2" /> <tr><td><h1><xsl:value-of select="$caption1" /></h1></td></tr> <tr><td><xsl:value-of select="$caption2" /></td></tr> </xsl:template> Usage: <table> <xsl:call-template name="TableHeader"> <xsl:with-param name="caption1">First Caption</xsl:with-param> <xsl:with-param name="caption2"> <xsl:call-template name="HrefTest" /> </xsl:with-param> </xsl:call-template> </table> Expected result: <table><tr><td><h1>First Caption</h1></td></tr><tr><td><h3>test</h3></td></tr></table> Actual result: <table><tr><td><h1>First Caption</h1></td></tr><tr><td>test</td></tr></table> No errors or anything, the tags just disappear. This is msxml6. Is this expected behavior, or do I need to somehow escape those tags, or what? Thanks -b
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