Subject: Re: [xsl] Skipping Custom Tags From: Michael B Allen <mba2000@xxxxxxxxxx> Date: Fri, 9 Dec 2005 14:42:43 -0500 |
On Fri, 9 Dec 2005 08:58:38 -0600 Jon Gorman <jonathan.gorman@xxxxxxxxx> wrote: > On 12/8/05, Michael B Allen <mba2000@xxxxxxxxxx> wrote: > > If I have a custom tag and I do: > > > > <xsl:apply-templates select="mytag"/> > > > > the tag <mytag> ends up in the output. > > Did you create an identity template that copied everything? Most Yes. I have the standard "Identity Transform" template that copies everything. > likely this is the case. Make it explicit that you don't want to copy > it: > > > Rather I want to skip that tag and apply-templates on everthing > > enclosed *within* that tag. For that, adding /* appears to work: > > > > <xsl:apply-templates select="mytag/*"/> > > > > Is this the proper expression or should it be "@*|node()" or what? > > Depends on your case, personally I wouldn't even use that. If it's > behavior you always want to occur, don't rely on the select, use > something like the below. > > <xsl:template match="mytag"> > <xsl:apply-templates /> > </xsl:template> > > That way, if you call <xsl:apply-templates /> somewhere you don't have > to worry about if there is a mytag element in there or not. Ah, yes. This is what I want. I see now that the Identity transform is copying it so I just need to provide a separate template that doesn't. Thanks, Mike
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