Subject: [xsl] RE: translate quote into quote quote From: "Philippe LAPLANCHE" <philippe.laplanche@xxxxxxxxxxxx> Date: Mon, 12 Dec 2005 07:29:37 +0100 |
I fixed it : <xsl:template name="escapeQuotes"> <xsl:param name="string"/> <xsl:variable name="apos">'</xsl:variable> <xsl:if test="not(contains($string,$apos))"><xsl:value-of select="$string"/></xsl:if> <xsl:if test="contains($string,$apos)"><xsl:value-of select="substring-before($string,$apos)"/><xsl:value-of select="$apos"/><xsl:value-of select="$apos"/><xsl:call-template name="escapeQuotes"><xsl:with-param name="string" select="substring-after($string,$apos)"/></xsl:call-template></xsl:if> </xsl:template> Philippe -----Message d'origine----- De : Philippe LAPLANCHE Envoyi : lundi 12 dicembre 2005 07:23 @ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx Objet : translate quote into quote quote Hi, I need to translate a string such as this one : I'm sad that I can't do it by myself Into : I''m sad that I can''t do it by myself I'm using XSLT 1.0, and I tried to do something like that : <xsl:template name="escapeQuotes"> <xsl:param name="string"/> <xsl:variable name="apos" select="'"/> <xsl:if test="not(contains($string,$apos))"><xsl:value-of select="$string"/></xsl:if> <xsl:if test="contains($string,$apos)"> <xsl:value-of select="substring-before($string,$apos)"/><xsl:value-of select="$apos"/><xsl:value-of select="$apos"/><xsl:call-template name="escapeQuotes"><xsl:with-param name="substring-after($string,$apos)"/></xsl:call-template> </xsl:if> </xsl:template> I'm doing something wrong ... Philippe
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