Subject: Re: [xsl] Concat Content of Node to Another? From: Jon Gorman <jonathan.gorman@xxxxxxxxx> Date: Mon, 12 Dec 2005 12:24:12 -0600 |
On 12/12/05, Donald M Rinderknecht <Donald.M.Rinderknecht@xxxxxxxx> wrote: > How can I concatenate the value of a node to a string, or actually value > of another node? concat(). > I am doing a replace() for the swf -> tif, but I can't figure out how to > get the path attached to the filename. > > I'm afraid I'm missing some basics, but I've searched to no avail. Look at both the w3's docs on XSLT and XPath. Most functions used by XSLT are actually part of the XPath spec. (At least as of version 1). concat([somepath]/imagepath,replace(Filename)) I've just stated [somepath] because I'm a little confused by the format at how you know which imagepath would be associated with which filename. Jon Gorman
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