Subject: Re: [xsl] trouble with preceding axis From: Duane Gran <duane.gran@xxxxxxxxx> Date: Tue, 3 Jan 2006 20:45:48 -0500 |
You might select the nearest preceding sibling like this,
<xsl:for-each select="/root/orange/preceding-sibling::*"> <xsl:if test="position() = last()"> <xsl:value-of select="name(.)"/> ... </xsl:if> </xsl:for-each>
Hope this is what you want.
Lisa
-----Original Message----- From: Duane Gran [mailto:duane.gran@xxxxxxxxx] Sent: Tuesday, January 03, 2006 1:20 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] trouble with preceding axis
Lisa,
Thank you very much. If you don't mind, I've run into another issue today with referencing the preceding element. Here is an example:
<root> <apple/> <pear/> <orange/> </root>
Given an xpath to orange (/root/orange) I want to reference the previous element which is a peer. I tried the following with no success:
/root/preceding::orange
I'm sure this is dreadfully simple, but I'm drawing a blank and I'm not seeing the answer in the tutorials I'm reading.
Duane
On Jan 3, 2006, at 2:52 PM, Xia Li wrote:
If you want to select the preceding <item> element of the <item> element whose child <label> element satisfies the predicate [label = 'subTitle'], you might try the following XPath expression,
//item[label = 'subTitle']/preceding::item
Lisa
-----Original Message----- From: Duane Gran [mailto:duane.gran@xxxxxxxxx] Sent: Tuesday, January 03, 2006 10:35 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] trouble with preceding axis
I'm having some trouble using the preceding axis in XPath and would be much obliged if someone could steer me in the right direction. I have the following document:
<root> <item order="3"> <label>Title</label> </item> <item order="4"> <label>subTitle</label> </item> </root>
I have the following XPath to select the second item, based on the value of its label child:
//item[label = 'subTitle']
Now I want to modify this so that I refer to the preceding item element, the first one in the list. I tried the following without success (it returns the second item element):
//preceding::item[label = 'subTitle']
Suggestions are most welcome on this.
Duane
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