Subject: Re: [xsl] Re: Collecting sibling nodes under groupings From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 13 Jan 2006 09:50:14 GMT |
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/"> <SubjectList> <xsl:for-each-group select="/List/Entry" group-by="Subject"> <SubjectEntry> <xsl:value-of select="Subject"/> <xsl:for-each select="current-group()"/> <Book> <xsl:copy-of select="*[not(self::Subject)]"/> </Book> </xsl:for-each> </SubjectEntry> </xsl:for-each-group> </SubjectList> </xsl:template> </xsl:stylesheet> ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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