Subject: Re: [xsl] Passing attributes in a node-set From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 17 Jan 2006 10:06:57 GMT |
when you do this <xsl:with-param name="value"> <root> <xsl:copy-of select="//element/@avalue"/> </root> </xsl:with-param> you make $value into a result tree fragment (not a node set) which corresponds to a node set with a root node with single child an element with name root which has no content but a single attribute avalue, with value equal to the last avalue attribute found in the input tree. You use it as <xsl:value-of select="$value"/> which gives the string value of the result tree fragment which is "" as element nodes with no content but with an attribute have empty string value. You want to make $value be the string value of teh attribute you find , something like <xsl:with-param name="value" select="string((//element/@avalue)[1])"/> which uses the first value, but I can not tell from your description which element you intend this parameter to use. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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