[xsl] Display unique values?

Subject: [xsl] Display unique values?
From: Alan Fenn <afenn262@xxxxxxxxx>
Date: Thu, 19 Jan 2006 20:32:01 -0800 (PST)
I'm an XSLT newbie, and have been struggling with
trying to extract unique values from an XML doc. I've
read Jeni's pages on the Muenchian technique, plus
some posts on the lists, but I can't find anything
that specifically relates to this.

Here's my XML snippet:

<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="sample.xslt"?>
<NewDataSet>
  <Archive>
    <Event>
      <ID>159</ID>
      <EventDevicesArchive>
        <EventDevice>
          <Device>2786</Device>
        </EventDevice>
        <EventDevice>
          <Device>2786</Device>
        </EventDevice>
      </EventDevicesArchive>
    </Event>
    <Event>
      <ID>160</ID>
      <EventDevicesArchive>
        <EventDevice>
          <Device>903</Device>
        </EventDevice>
        <EventDevice>
          <Device>904</Device>
        </EventDevice>
        <EventDevice>
          <Device>903</Device>
        </EventDevice>
      </EventDevicesArchive>
     </Event>
    <Event>
      <ID>161</ID>
      <EventDevicesArchive>
        <EventDevice>
          <Device>2786</Device>
        </EventDevice>
        <EventDevice>
          <Device>2787</Device>
        </EventDevice>
        <EventDevice>
          <Device>2787</Device>
        </EventDevice>
      </EventDevicesArchive>
    </Event>
    <Event>
      <ID>162</ID>
      <EventDevicesArchive>
        <EventDevice>
          <Device>903</Device>
        </EventDevice>
        <EventDevice>
          <Device>904</Device>
        </EventDevice>
        <EventDevice>
          <Device>903</Device>
        </EventDevice>
      </EventDevicesArchive>
     </Event>
  </Archive>
</NewDataSet>

and here's the XSLT I've tried:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2005/02/xpath-functions";
xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes";>
<xsl:output version="1.0" encoding="UTF-8" indent="no"
omit-xml-declaration="no" media-type="text/html" />
<xsl:key name="IncidentID" match="Event" use="ID" />
<xsl:key name="DeviceID" match="Event" use="concat(ID,
' ', EventDevicesArchive/EventDevice/Device)" />
    <xsl:template match="/">
    <html>
       <table>
          <thead>
            <tr>
              <td>Event</td>
              <td>Device</td>
            </tr>
          </thead>
          <tbody>
          <xsl:for-each
select="NewDataSet/Archive/Event">
            <tr>
              <td>
                <xsl:value-of select="ID"/>
              </td>
              <td>
                <xsl:variable name="DeviceItems"
select="key('IncidentID', ID)" />
                <xsl:for-each
select="EventDevicesArchive/EventDevice">
                  <xsl:for-each
select="$DeviceItems[generate-id() =
generate-id(key('DeviceID', concat(ID, ' ',
EventDevicesArchive/EventDevice/Device))[1])]">
                    <xsl:if test="position()!=1">
                      <xsl:text>, </xsl:text>
                    </xsl:if>
                    <xsl:value-of select="Device" />
                  </xsl:for-each>
                </xsl:for-each>
              </td>
            </tr>
          </xsl:for-each>
        </tbody>
      </table>  
    </html>
  </xsl:template>
</xsl:stylesheet>

The desired output is:

ID   Device
159  2786
160  903, 904
161  2786, 2787
162  903, 904
 
With the above, all I get is:

ID    Device
159  
160  
161  
162  

I've also tried variations that return all the
devices, and a list of devices that are unique to the
entire document, not each event. Any ideas?


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