Subject: [xsl] Display unique values? From: Alan Fenn <afenn262@xxxxxxxxx> Date: Thu, 19 Jan 2006 20:32:01 -0800 (PST) |
I'm an XSLT newbie, and have been struggling with trying to extract unique values from an XML doc. I've read Jeni's pages on the Muenchian technique, plus some posts on the lists, but I can't find anything that specifically relates to this. Here's my XML snippet: <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="sample.xslt"?> <NewDataSet> <Archive> <Event> <ID>159</ID> <EventDevicesArchive> <EventDevice> <Device>2786</Device> </EventDevice> <EventDevice> <Device>2786</Device> </EventDevice> </EventDevicesArchive> </Event> <Event> <ID>160</ID> <EventDevicesArchive> <EventDevice> <Device>903</Device> </EventDevice> <EventDevice> <Device>904</Device> </EventDevice> <EventDevice> <Device>903</Device> </EventDevice> </EventDevicesArchive> </Event> <Event> <ID>161</ID> <EventDevicesArchive> <EventDevice> <Device>2786</Device> </EventDevice> <EventDevice> <Device>2787</Device> </EventDevice> <EventDevice> <Device>2787</Device> </EventDevice> </EventDevicesArchive> </Event> <Event> <ID>162</ID> <EventDevicesArchive> <EventDevice> <Device>903</Device> </EventDevice> <EventDevice> <Device>904</Device> </EventDevice> <EventDevice> <Device>903</Device> </EventDevice> </EventDevicesArchive> </Event> </Archive> </NewDataSet> and here's the XSLT I've tried: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/02/xpath-functions" xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes"> <xsl:output version="1.0" encoding="UTF-8" indent="no" omit-xml-declaration="no" media-type="text/html" /> <xsl:key name="IncidentID" match="Event" use="ID" /> <xsl:key name="DeviceID" match="Event" use="concat(ID, ' ', EventDevicesArchive/EventDevice/Device)" /> <xsl:template match="/"> <html> <table> <thead> <tr> <td>Event</td> <td>Device</td> </tr> </thead> <tbody> <xsl:for-each select="NewDataSet/Archive/Event"> <tr> <td> <xsl:value-of select="ID"/> </td> <td> <xsl:variable name="DeviceItems" select="key('IncidentID', ID)" /> <xsl:for-each select="EventDevicesArchive/EventDevice"> <xsl:for-each select="$DeviceItems[generate-id() = generate-id(key('DeviceID', concat(ID, ' ', EventDevicesArchive/EventDevice/Device))[1])]"> <xsl:if test="position()!=1"> <xsl:text>, </xsl:text> </xsl:if> <xsl:value-of select="Device" /> </xsl:for-each> </xsl:for-each> </td> </tr> </xsl:for-each> </tbody> </table> </html> </xsl:template> </xsl:stylesheet> The desired output is: ID Device 159 2786 160 903, 904 161 2786, 2787 162 903, 904 With the above, all I get is: ID Device 159 160 161 162 I've also tried variations that return all the devices, and a list of devices that are unique to the entire document, not each event. Any ideas? __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
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