Re: [xsl] Unable to get text() of node

Subject: Re: [xsl] Unable to get text() of node
From: "Liron" <magilam@xxxxxxxxxxxxxxxx>
Date: Sat, 21 Jan 2006 21:35:21 +0100
Hi Andrew,

Thank you very much for your reply.

It works!

As for your mixed content comment - You're absolutely right but I'm taking care of it.
In my project I'm actually applying xsl on html thus the use of mixed content for children.


Thanks again, I'm learning a lot from all the replies I get
Liron

----- Original Message ----- From: "andrew welch" <andrew.j.welch@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Saturday, January 21, 2006 8:59 PM
Subject: Re: [xsl] Unable to get text() of node



You can use the following stylesheet:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
 <tree>
   <xsl:apply-templates select="tree/child[childname]"/>
 </tree>
</xsl:template>

<xsl:template match="child">
 <childText>
   <xsl:apply-templates/>
 </childText>
</xsl:template>

<xsl:template match="childname"/>

</xsl:stylesheet>

But I would suggest that you source XML structure should be changed
because when you have:

<node>
  <child/>
  Some text
</node>

All the presentational whitespace surrounding "Some text" is part of
the value (the first carriage return, the indentation and the second
CR), which is not the intention.

Having mixed content like that isn't really suitable for data-centric
XML as this problem has demonstrated - its much better to have an
element for each value, and each element should only contain other
elements, or text, but not both eg:

<node>
  <child/>
  <child>Some text</child>
</node>

cheers
andrew

Current Thread