RE: RE: [xsl] Creating XPath2 functions:passing a set of nodes, what is the signature construction?

[cknell@xxxxxxxxxx]

Thanks, I couldn't find that. On closer examination, it seems the standard set of XPath2 functions does not include a square root function. I don't feel up to writing my own, so I won't procede with the standard deviation function.
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Xia Li <xli@xxxxxxxxxxxxx>
Sent:     Wed, 25 Jan 2006 13:46:02 -0800
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  RE: [xsl] Creating XPath2 functions:passing a set of nodes, what is the signature construction?

You may use occurrence indicator "*" or "+" in <xsl:param>, such as

<xsl:param ... as="xs:double*"> 

to indicate that a sequence of double is expected. 


Lisa
 

-----Original Message-----
From: cknell@xxxxxxxxxx [mailto:cknell@xxxxxxxxxx] 
Sent: Wednesday, January 25, 2006 1:26 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Creating XPath2 functions:passing a set of nodes, what is
the signature construction?

I am learning XPath2 using Saxon 8.6. I'd like to create a funtion to
compute the standard deviation of the value of a set of nodes. Is there
some special way to construct the signature of the function when the
argument is a set of nodes as opposed to a single node?

I have written a funtion that takes a single node as an argument of type
xs:double. Is there some special way to state that the function will
take a set of nodes of type xs:double, or do I simply state that the
argument will be of type xs:double?

-- 
Charles Knell
cknell@xxxxxxxxxx - email