Re: [xsl] Including <?xml ...> in the result tree

Subject: Re: [xsl] Including <?xml ...> in the result tree
From: Sebastian Tennant <sebyte@xxxxxxxxxxxxxxx>
Date: Mon, 30 Jan 2006 01:34:52 +0000
"Michael Kay" <mike@xxxxxxxxxxxx> wrote:

> In both cases, the relevant construct is not part of the result tree, so
> it's created during serialization rather than during transformation. (If you
> look at the data model, you'll see that neither the XML declaration nor the
> DOCTYPE declaration appear as nodes in the tree).
>
> You generate all of this with attributes of xsl:output: method="xml",
> version="1.0", encoding="UTF-8", doctype-system and doctype-public.
>
> The only thing an XML declaration and a processing instruction have in
> common is that they both start with "<?".
>
> Michael Kay
> http://www.saxonica.com/ 

Thanks Michael, I got there myself, but your explanation makes things
even clearer.

sdt

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