Subject: Re: [xsl] Printing all child bachelor nodes From: andrew welch <andrew.j.welch@xxxxxxxxx> Date: Thu, 9 Feb 2006 15:28:23 +0000 |
On 2/9/06, Douglas F Shearer <dougal.s@xxxxxxxxx> wrote: > Hi there. > > I have the following snippet of XML and would like to extract the > data given below using XSL... > > ********** XML ************ > <features> > <pool length="30" max-depth="160" min-depth="30" indoor="false"/> > <DVD/> > <beds twin="2" sofa-bed="1"/> > </features> > > ******** REQUIRED OUTPUT ****** > pool: length: 30, max-depth:160, min-depth:30, indoor: false. > DVD. > beds: twin:2, sofa-bed:1 > > ************************************** > > The main issue I am having is that the nodes themselves change > (microwave instead of DVD etc). Basically I want to print out all of > the elements within the features element, and their associated > attributes. <xsl:template match="features/*"> <xsl:value-of select="local-name()"/> <xsl:for-each select="@*"> <xsl:value-of select="concat(' ', name(), ':', .)"/> <xsl:if test="position() != last()">,</xsl:if> </xsl:for-each> <xsl:text>.</xsl:text> </xsl:template> Did you really want text output? If so you will need to add CRs in there, but I'm guess you'll be using HTML. Also, beds didn't end with a . which I'm also assuming was a typo. cheers andrew
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