Re: [xsl] joining nodes

[Rolf Schumacher <mailinglist@xxxxxxxxx>]

Yes, thank you for the link.
The solving method is called "Muenchian Method".
If I would have performance problems there are improvements possible.

However, the first method fits for me.

Rolf

Michael Kay wrote:

> I'm having difficulty abstracting your two specific problems to identify the
> general problem that you want to solve.
>
> However, they're both in the area called "grouping", and you can get
> guidance at http://www.jenitennison.com/xslt/grouping.
>
> Michael Kay
> http://www.saxonica.com/
>
>
>
>  
>
> > -----Original Message-----
> > From: mailinglist@xxxxxxxxx [mailto:mailinglist@xxxxxxxxx] 
> > Sent: 16 February 2006 15:12
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] joining nodes
> >
> > I'm about new to XSLT and would like to ask you for help before I pay
> > another unsuccessful weekend.
> >
> > I would like to join nodes. Can you point me to some words of how to
> > achieve that?
> >
> > I'll describe the task in two examples. The perfect answer to 
> > my question
> > would be a stylesheet, but a hint can do as well.
> >
> > Input:
> > <join1>
> > <aaa>
> >  <a>
> >    <name>n1</name>
> >    <value1>v11</value1>
> >  </a>
> >  <a>
> >    <name>n2</name>
> >    <value1>v12</value1>
> >  </a>
> > </aaa>
> > <bbb>
> >  <a>
> >    <name>n1</name>
> >    <value2>v21</value2>
> >  </a>
> >  <a>
> >    <name>n2</name>
> >    <value2>v22</value2>
> >  </a>
> > </bbb>
> > </join1>
> >
> > should be transformed to the (text) output:
> >
> > n1
> >  v11
> >  v21
> > n2
> >  v21
> >  v22
> >
> > because n1 is associated to v11 and v21 and n2 is associated 
> > to v21 and
> > v22 in <aaa/> and <bbb/> respectively.
> >
> > <join2>
> > <aaa>
> >  <ident>id1</ident>
> >  <ident>id3</ident>
> > </aaa>
> > <bbb>
> >  <ccc>
> >    <ident>id1</ident>
> >    <subject>sb1</subject>
> >  </ccc>
> >  <ccc>
> >    <ident>id2</ident>
> >    <subject>sb2</subject>
> >  </ccc>
> >  <ccc>
> >    <ident>id3</ident>
> >    <subject>sb3</subject>
> >  </ccc>
> > </bbb>
> > </join2>
> >
> > should be transformed to the (text) output:
> >
> > id1 sb1
> > id3 sb3
> >
> > because id2 is missing in <aaa/>
> >
> > I tried nested for-each but didn't succeed. I had no clue how 
> > to address
> > this task with template rules.
> >
> > Thanks in advance
> >
> > rolf