Re: [xsl] xsl 2.0 recursive functions and return value

[Joern Nettingsmeier <nettings@xxxxxxxxxxxxxxxxxxxxxx>]

replying to myself here...

Joern Nettingsmeier wrote:
> hi everyone!
>
>
> i'm trying to write a branching recursive function, but i have a problem 
> with the "xsl:sequence" being non-terminating.
>
> how can i get the following to work:
<snip>

i could think of this solution:


<xsl:function name="r2c:__hasTextContent" as="xs:boolean?">
  <xsl:param name="node"/>
  <xsl:for-each select="$node/*">
    <xsl:choose>
      <xsl:when test="r2c:isOutputNode(.)"/>
      <xsl:when test="r2c:isLeafNode(.)">
        <xsl:sequence select="true()"/>
      </xsl:when>
      <xsl:otherwise>
        <xsl:sequence select="r2c:hasTextContent(.)"/>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:for-each>
</xsl:function>

<xsl:function name="r2c:hasTextContent" as="xs:boolean">
  <xsl:param name="node"/>
  <xsl:choose>
    <xsl:when test="r2c:__hasTextContent($node)">
      <xsl:sequence select="true()"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:sequence select="false()"/>
    </xsl:otherwise>
  <xsl:choose>
</xsl:function>


but at a time where i'm still dancing in the courtyard chanting "no more 
ugliness in the world" after having discovered xsl 2.0, this one is a 
bit of a spoil. :(

is there a solution which, in addition to working, is actually beautiful?
(i know i could easily get rid of the wrapper in this case since the 
empty set evaluates to "false", but i'm looking for a general solution 
that will also apply to non-boolean functions.)


regards,

jC6rn


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