RE: [xsl] Problem getting position of node

["Michael Kay" <mike@xxxxxxxxxxxx>]

By the "position" of the node I imagine you mean the number of preceding
sibling nodes (or elements?) plus one. You can get that using

count(preceding-sibling::node()) + 1

or

count(preceding-sibling::*) + 1 

depending which you want.

You can also use <xsl:number/>.

The position() function gives you something quite different: its value is
unrelated to the position of a node in the tree, it depends only on the
position of the node within the sequence of nodes currently selected for
processing.

>   Error in expression concat(., parent::node()/position()): Unexpected
> token [<function>] in path expression

XSLT 1.0 doesn't allow a function call on the rhs of "/". XSLT 2.0 does. But
parent::node()/position() will always return 1: a node has only one parent
and the position of that parent among all the parents is therefore always 1.

Michael Kay
http://www.saxonica.com/