Re: [xsl] Finding element name of content node

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Ed,

At 10:59 AM 4/11/2006, you wrote:
> I can't seem to find the answer to this question anywhere.  Can someone
> help?

Yep. (Odd that you can't find the answer.)

> How do I find out the name of the current content node?

If I understand what you mean by the "current content node", you want 
the XPath function "name()" (for the namespace-qualified name) or 
"local-name()" (the unqualified name). Use either one without an 
argument and retrieve the name of the context node by default.

The Mulberry XSLT Quick Reference, available for download at 
http://www.mulberrytech.com/quickref/index.html, lists all the XPath 
functions and operators (in addition to much else). While it doesn't 
explain what they are for, it does elucidate their syntax, and 
usually their names provide good hints (to English speakers anyway 
:-) as to their semantics. Once you know the name of a function you 
think might do the job, a search engine gives you all the help you need.

The "horse's mouth" in this case is the W3C spec itself: the XPath 
1.0 Recommendation is at http://www.w3.org/TR/xpath).

Good luck,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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