Re: [xsl] Question about cross references

["Tech Savvy" <tecsavvy@xxxxxxxxx>]

Hi:

Sorry about that, I must have done a reply instead of a reply-all.

I am currently trying to achieve this on XSLT.

This is what I did:

I declared a key for the ids...

<xsl:key  name="steps" match="*[@id]" use="@id"/>


And on the xref template:
<xsl:template match="xref">

	<a href="@xrefid">
      <xsl:for-each select="key('steps',@xrefid)">

                        <xsl:number count="list1" level="any"
    format="1"/>
                </xsl:for-each>
</a>
	</xsl:template>

Any suggestions on this approach?

On 4/27/06, Jay Bryant <jay@xxxxxxxxxxxx> wrote:
> First, an admin thing: all traffic should go to the list. Down the road,
> someone will have the same question, and they might find the answer in the
> archives if we keep all the traffic on the list. Writing to someone
directly
> probably doesn't get a faster or better response, and it robs the archive
of
> potentially useful information. I've cc'd the list to get us back on track.
>
> From your earlier post, I suspect that the following template is the source
> of your problem:
>
> <xsl:template match="xref">
>
> <xsl:apply-templates select="@xrefid"/>
>
> </xsl:template>
>
>
> Do you have a template to handle that attribute or are you letting your
XSLT
> processor take its default behavior (which is to put the text value of the
> attribute into the output)? If you are letting it take its default
behavior,
> you'll never get the FO tags you need.
>
> Also, it's easier (and more maintainable) to just do it all here in this
> template rather than call another one from this point.
>
> To say more, I'd have to see more of your transform.
>
> Jay Bryant
> Bryant Communication Services
>
> ----- Original Message -----
> From: "Tech Savvy" <tecsavvy@xxxxxxxxx>
> To: <jay@xxxxxxxxxxxx>
> Sent: Thursday, April 27, 2006 10:35 AM
> Subject: Re: [xsl] Question about cross references
>
>
> Hello:
>
> I have still not been able to find a solution to this problem. Would
> you have any other suggestions to this.
>
> Thank you
>
>
>
>
> On 4/26/06, Jay Bryant <jay@xxxxxxxxxxxx> wrote:
> > That's very possible (and a common task for those of us, including me,
who
> > use XSLT to mangle documents).
> >
> > To handle it, you need to write a template to handle xref nodes.
Something
> > like this:
> >
> > <xsl:template match="xref">
> >  <fo:basic-link internal-destination="{@xrefid}"><xsl:value-of
> > select="."/></fo:basic-link>
> > </xsl:template>
> >
> > You also need to create matching ids (the actual destinations) within the
> > FO, so you need to do that wherever you have an id attribute in the
> source.
> > Something like this:
> >
> > <xsl:template match="list1">
> >  <fo:block>
> >    <xsl:if test="@id">
> >      <xsl:copy-of select="@id"/>
> >    </xsl:if>
> >    <xsl:value-of select="."/>
> >  </fo:block>
> > </xsl:template>
> >
> > Of course, you'll probably want to use the proper list elements for your
> > list. I just stuck it in a block for simplicity's sake.
> >
> > Just remember that you need both a link and a corresponding id for the
> link.
> >
> > Also, if you can have id attributes in other than list1 nodes (seems
> > likely), you'll want to either handle it in each template or write a
> > separate template just to handle id attributes.
> >
> > If you have more trouble, post back to the list.
> >
> > HTH
> >
> > Jay Bryant
> > Bryant Communication Services
> >
> > ----- Original Message -----
> > From: "Tech Savvy" <tecsavvy@xxxxxxxxx>
> > To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> > Sent: Wednesday, April 26, 2006 1:39 PM
> > Subject: [xsl] Question about cross references
> >
> >
> > Hello:
> >
> > I am trying to achieve a corss ref in xslt and xsl:fo.
> >
> > Here is wht the XML looks like:
> > <
> >
> > list1 id="l1">
> > <text>
> >
> > <para>Some text</para>
> >
> > </text>
> >
> > </list1>
> >
> > <list1 id="l2">
> >
> >
> > <text>
> >
> > <para>Some other text as in list <xref xrefid ="l1"/>A.</para>
> >
> > </text>
> >
> > </list1>
> >
> > The desired result is:
> >
> > 1. Some text
> > 2. Some other text as in list 1A.
> >
> > But the current result is:
> > 1. Some text
> > 2. Some other text as in list l1A.
> >
> >
> > I want to get the reference from the xrefid and put it on the text.
> > The lists are formatted on the XSLT as eithr numbers(1,2) or (A,B)
> > etc.
> >
> > Is there nay way this can be achieved thru XSLT.
> >
> > Thanks in advance for your help.