Re: [xsl] Converting an xml to another xml Using XSLT

["Jon Gorman" <jonathan.gorman@xxxxxxxxx>]

> I need suggestion or solution how to handle arbitary depth i.e. if
> "classitem" depth is 5 or 8 or some other value.
Right.....but the confusion is why you're checking for the depth
anyhow.  The entire point of XSLT is that the processor can do the
work of traveling for the tree for you.  If you always do the same
thing regardless of depth, just put it into one template.  To repeat
my code templates before (with them cleaned up a little):

<xsl:template match="class">
<hier>
<xsl:apply-templates />
</hier>
</xsl:template>

<xsl:template match="classitem">
<hierlev>
<heading>
 <title><xsl:value-of select="identifier/name" /></title>
</heading>
<xsl:apply-templates />
</hierlev>
</xsl:template>

<xsl:template match="identifier" />
<xsl:template match="code" />

Given these templates, the code will always produce
<hierlev>
<heading>
<title>name</title>
</head>
...whatever output applying templates to children element
<hierlev>

when it sees a classitem element.


XSLT by default uses recursive travel of the document tree.

Now, a variation might be that you need to do something different
based off the depth of the element in the tree.  Off the top of my
head counting the nodes in the ancestor axis would be the way to do
that.


Jon Gorman