RE: [xsl] Special characters and Transformation

Subject: RE: [xsl] Special characters and Transformation
From: "Khorasani, Houman" <Houman.Khorasani@xxxxxxxxxxxx>
Date: Fri, 5 May 2006 11:47:40 +0100
Sorry, the sample I am using is more complicated than the one I have shown
here.  I made a mistake.  In real the root has children.

My problem here is the for-each statement

<xsl:for-each select="root/TEXT">

Because root has a namespace:

<root xmlns="";>

So I have to make my for-each element to understand that the "root" with the
following namespace has a "TEXT" tag.  But I don't know yet how...

Thanks for the references, I will have a look and hopefully find something.
That should be straight forward...


-----Original Message-----
From: Florent Georges [mailto:darkman_spam@xxxxxxxx]
Sent: 05 May 2006 11:33
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Special characters and Transformation

"Khorasani, Houman" wrote:

> 2) For some reason I can't even reproduce the problem.
> I only get a root with namespace and all elements are
> empty underneath.

> I tried this:
>  <?xml version="1.0" encoding="us-ascii"?>
>  <xsl:stylesheet version="1.0"
>  xmlns:xsl="";>
>  	<xsl:output method="xml" version="1.0" encoding="us-ascii"
> indent="yes"/>
>  	<xsl:template match="/">
>  		<xsl:element name="root" namespace="";>
>  			<xsl:for-each select="Text">
>  				<xsl:element name="Text">
>  					<xsl:element name="tag">
>  						<xsl:value-of select="tag"/>
>  					</xsl:element>
>  				</xsl:element>
>  			</xsl:for-each>
>  		</xsl:element>
>  	</xsl:template>
>  </xsl:stylesheet>

  You don't have any 'Text' children of your root node (in the sample
you provided).  Use instead:

    <xsl:for-each select="root/Text">

  BTW, I suggest you to take a look at "Literal Result Elements",
"Template Rules", and maybe the "Modified Identity Tranformation



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