Re: [xsl] Preserve CDATA for all elements

Subject: Re: [xsl] Preserve CDATA for all elements
From: George Cristian Bina <george@xxxxxxxxxxxxx>
Date: Sun, 14 May 2006 20:50:42 +0300
No, you cannot use * to refer to all the elements, you need to specify them all as cdata-section-elements contains a list of qualified names as its value. Note that in cdata-section-elements you specify the elements in the *output* not in the *source* XML.

Best Regards,
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger

Jagdishwar (Jagsmiles) wrote:
I would like to put the <![CDATA[ elements as is in my transformed xml.
So, i had used following declaration at the beginning of the xsl:
    <xsl:output method="xml" cdata-section-elements="elementOne
elementTwo elementThree"/>

Its works fine for transforming the specified elements (i.e elementOne
elementTwo elementThree) along with the CDATA.

Actually i want to preserve CDATA as is, in all the elements my source xml.
But Its not very comfortable to add each and every element to the
cdata-section-elements attribute.

I tried using * instead of the element names.
    <xsl:output method="xml" cdata-section-elements="*"/>
but it does not work, the xslt transformer says:
"This name may not contain the '*' character"

But * works fine in other elements like xsl:strip-space
    <xsl:strip-space elements="*"/>

Is there any way, where i can specify in xsl, to preserve all the
CDATA for all the elements of the source xml document.

Thank you all

Kind Regards,
Jagsmiles @

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