Re: [xsl] Preserve CDATA for all elements

[George Cristian Bina <george@xxxxxxxxxxxxx>]

No, you cannot use * to refer to all the elements, you need to specify 
them all as cdata-section-elements contains a list of qualified names as 
its value. Note that in cdata-section-elements you specify the elements 
in the *output* not in the *source* XML.

Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com


Jagdishwar (Jagsmiles) wrote:
> I would like to put the <![CDATA[ elements as is in my transformed xml.
> So, i had used following declaration at the beginning of the xsl:
>     <xsl:output method="xml" cdata-section-elements="elementOne
> elementTwo elementThree"/>
>
> Its works fine for transforming the specified elements (i.e elementOne
> elementTwo elementThree) along with the CDATA.
>
> Actually i want to preserve CDATA as is, in all the elements my source xml.
> But Its not very comfortable to add each and every element to the
> cdata-section-elements attribute.
>
> I tried using * instead of the element names.
>     <xsl:output method="xml" cdata-section-elements="*"/>
> but it does not work, the xslt transformer says:
> "This name may not contain the '*' character"
>
> But * works fine in other elements like xsl:strip-space
>     <xsl:strip-space elements="*"/>
>
> Is there any way, where i can specify in xsl, to preserve all the
> CDATA for all the elements of the source xml document.
>
> Thank you all
>
> Kind Regards,
> Jagdishwar,
> Jagsmiles @ gmail.com