RE: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic

Subject: RE: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic
From: "Karen McAdams" <kamcadam@xxxxxxxxx>
Date: Wed, 17 May 2006 14:52:54 -0700
Dave Pawsons' FAQ covers date processing here for xslt2

Which version and processor are you using?


-----Original Message-----
From: cknell@xxxxxxxxxx [mailto:cknell@xxxxxxxxxx]
Sent: Wednesday, May 17, 2006 2:30 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic

Given a parameter, let's call it "today" in the form of this string
"20060517", how do I create a variable, let's call it "tMinus1" such
that it represents a day earlier than "20060517", that would be
"20060516". So long as "$today" isn't the first day of a month, a simple
subtraction and followed by a type cast that I don't grasp would do the

What I'm looking for is guidance on date arithmetic.


Charles Knell
cknell@xxxxxxxxxx - email

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