Subject: Re: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic|
From: Andrew Franz <afranz0@xxxxxxxxxxxxxxxx>
Date: Thu, 18 May 2006 22:50:45 +1000
Given a parameter, let's call it "today" in the form of this string "20060517", how do I create a variable, let's call it "tMinus1" such that it represents a day earlier than "20060517", that would be "20060516". So long as "$today" isn't the first day of a month, a simple subtraction and followed by a type cast that I don't grasp would do the trick.
What I'm looking for is guidance on date arithmetic.
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