Subject: [xsl] XML to HTML transform validation problem From: "Trevor Nicholls" <trevor@xxxxxxxxxxxxxxxxxx> Date: Fri, 26 May 2006 18:56:31 +1200 |
I have a set of XML documents and a standard XML-HTML transformation which is run in a pipeline; the XSL processor is Saxon 8.6.n (can't check at the moment, but I think n=1). Because of the way the stylesheet needs to process footnotes I have to use some XSL 2.0 features, hence there is some typing in the stylesheet (..as="xs:integer"..) and the stylesheet has to declare the xs namespace. ========= XSL ======== <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" > <xsl:output method="html" encoding="ISO-8859-1" indent="no" doctype-public="-//W3C//DTD HTML 4.01 Transitional//EN" doctype-system="http://www.w3.org/TR/html4/loose.dtd" /> <xsl:template match="/document"> <html> <head> <title><xsl:value-of select="title" /></title> </head> <body> ...etc... </body> </html> ...etc... ===================== I am putting the generated HTML through the HTML validator (at http://validator.w3.org) and getting errors; the first of which is Error: there is no attribute "XMLNS:XS". <html xmlns:xs="http://www.w3.org/2001/XMLSchema"><head><title... If I drop the xmlns:xs declaration from my stylesheet (and comment out the 2.0 features it uses) then the <html> element does not declare the namespace, but this isn't the right answer! I can see plenty of example HTML outputs on the standard XSL websites which declare the same namespace, so what additional step do I have to take to produce output which validates? I can't believe that everybody's examples would fail the validation tests, so obviously I've missed something. Thanks for any help Cheers Trevor
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