Subject: [xsl] "not a node item" inside distinct-values From: "Rick Roen" <Rick@xxxxxxxxxxxxxxxxxx> Date: Thu, 8 Jun 2006 08:56:40 -0500 |
XSLT 2.0 XML Spy I have the following snippet of xml: <item racknum="1" traynum="7" pocketnum="11" itemnum="176" qty_ship="12">SQUASH BENNINGS GREEN TINT</item> <item racknum="1" traynum="7" pocketnum="12" itemnum="177" qty_ship="42">SQUASH BLACK BEAUTY</item> <item racknum="1" traynum="7" pocketnum="13" itemnum="178" qty_ship="18">SQUASH EARLY PROLIFIC STRAIGHT NECK</item> <item racknum="2" traynum="8" pocketnum="1" itemnum="179" qty_ship="12">SQUASH EARLY SUMMER CROOKNECK</item> <item racknum="2" traynum="8" pocketnum="2" itemnum="180" qty_ship="6">SWISS CHARD FORDHOOK GIANT</item> <item racknum="2" traynum="8" pocketnum="3" itemnum="183" qty_ship="24">TOMATO CELEBRITY HYBRID</item> <item racknum="2" traynum="8" pocketnum="4" itemnum="204" qty_ship="24">TOMATO FLAVOR KING HYBRID</item> <item racknum="2" traynum="8" pocketnum="5" itemnum="186" qty_ship="30">WATERMELON CRIMSON SWEET</item> <item racknum="2" traynum="8" pocketnum="6" itemnum="205" qty_ship="12">WATERMELON SUGAR BABY</item> I want to get the largest @pocketnum for each @racknum, i.e. racknum = 1 largest pocketnum = 13, racknum = 2 largest pocketnum = 6 My XSLT is like this: <xsl:for-each select="distinct-values(//item/@racknum)"> <xsl:variable name="rack-num" select="."/> <xsl:variable name="pocket-num" select="//item[./@racknum = $rack-num and position() = last()]"/> <p>Rack: <xsl:value-of select="$rack-num"/> max pocket: <xsl:value-of select="$pocket-num"/></p> </xsl:for-each> I get an error "Error in XPath 2.0 expression Not a node item" Oustide of the <xsl:for-each... I can use: <xsl:value-of select="//item[./@racknum = 2 and position() = last()]/@pocketnum"/> and get the results I expect, i.e. 6. This must have something to do with the context within the "for-each", but I can't figure out how to get the information. Any suggestions? Rick
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