[xsl] RE : RE: [xsl] root siblings contain xmlns=""

[Florent Georges <darkman_spam@xxxxxxxx>]

christoph.klocker@xxxxxx wrote:

  Hi

> test.xml:
> <test >
>     <element1>test</element1>
>     <element2>test</element2>
> </test>

> test.xsl:

> [...]

> output:
> <?xml version="1.0" encoding="UTF-8"?><Fxml xmlns="a-namespace-uri"
> Version="2_0_2">
>     <element1 xmlns="">test</element1>
>     <element2 xmlns="">test</element2>
> </Fxml>

> my desired output:
> <?xml version="1.0" encoding="UTF-8"?><Fxml xmlns="a-namespace-uri"
> Version="2_0_2">
>     <element1>test</element1>
>     <element2 >test</element2>
> </Fxml>

  You are copying elements from no namespace, and want to have them in
a specific namespace.  So you have to make something more than just
copy them.  For example (depending on the exact semantics of your
transformation):

    <xsl:template match="@*|node()" piority="0">
      <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
      </xsl:copy>
    </xsl:template>

    <xsl:template match="*">
      <xsl:element name="{local-name()}" namespace="...">
        <xsl:apply-templates select="@*|node()"/>
      </xsl:element>
    </xsl:template>

  Not tested.

  Regards,

--drkm























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