Subject: RE: [xsl] Grouping elements using XSLT From: "Rick Roen" <Rick@xxxxxxxxxxxxxxxxxx> Date: Tue, 20 Jun 2006 15:53:49 -0500 |
SORRY, that was wrong. Following-sibling selects ALL nodes that follow, so you want select="following-sibling[1]" Rick -----Original Message----- From: Rick Roen [mailto:Rick@xxxxxxxxxxxxxxxxxx] Sent: Tuesday, June 20, 2006 3:42 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] Grouping elements using XSLT If they are always in this order <FirstName> then <LastName> you can get all the nodes in <author>, then for each <FirstName> element you can select the following-sibling:: which should get the <LastName> element. Something like this: <xsl:for-each select="author/FirstName" > <author> <xsl:value-of select="." /> <xsl:value-of select="following-sibling[ name() = 'LastName' ]" /> </author> </xsl:for-each> I added a test to make sure the following-sibling is indeed LastName, but I'm not sure if this is necessary. Untested! Rick -----Original Message----- From: Chad Chelius [mailto:cchelius@xxxxxxxxxxxxxxx] Sent: Tuesday, June 20, 2006 3:18 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Grouping elements using XSLT I have an XML file that looks like this: <author> <Firstname>Jane</FirstName> <LastName>Doe</Doe> <Firstname>John</FirstName> <LastName>Doe</Doe> <Firstname>Howard</FirstName> <LastName>Johnson</Doe> </author> The DTD that I am trying to validate to requires that each person be inside of their own <author> element like this: <author> <Firstname>Jane</FirstName> <LastName>Doe</Doe> </author> <author> <Firstname>John</FirstName> <LastName>Doe</Doe> </author> <author> <Firstname>Howard</FirstName> <LastName>Johnson</Doe> </author> Is this possible using an XSLT and if so, how do you do this?
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