Re: [xsl] simulating for with foreach

Subject: Re: [xsl] simulating for with foreach
From: "Mohsen Saboorian" <mohsens@xxxxxxxxx>
Date: Wed, 5 Jul 2006 14:51:04 +0330

Thanks again,

<xsl:for-each select="node[position() mod 4 = 1]">

This is exactly what I want, but although this for-each iterates over
1, 5, 9, ... elements, when I print position() inside this loop, it
prints 1, 2, 3, 4, ...

How can I figutre out which child element is now selected, 1? 5? ...

Current Thread
Re: [xsl] simulating for with foreach, (continued) David Carlisle - Wed, 5 Jul 2006 10:37:58 +0100 Message not available Mohsen Saboorian - Wed, 5 Jul 2006 14:06:17 +0330 David Carlisle - Wed, 5 Jul 2006 11:54:56 +0100 David Carlisle - Wed, 5 Jul 2006 12:00:48 +0100 Mohsen Saboorian - Wed, 5 Jul 2006 14:51:04 +0330 <= David Carlisle - Wed, 5 Jul 2006 12:29:37 +0100 Mohsen Saboorian - Wed, 5 Jul 2006 15:22:06 +0330 David Carlisle - Wed, 5 Jul 2006 13:11:43 +0100 Michael Kay - Wed, 5 Jul 2006 13:01:32 +0100

Current Thread

Re: [xsl] simulating for with foreach, (continued)
- David Carlisle - Wed, 5 Jul 2006 10:37:58 +0100
  - Message not available
    - Mohsen Saboorian - Wed, 5 Jul 2006 14:06:17 +0330
    - David Carlisle - Wed, 5 Jul 2006 11:54:56 +0100
    - David Carlisle - Wed, 5 Jul 2006 12:00:48 +0100
    - Mohsen Saboorian - Wed, 5 Jul 2006 14:51:04 +0330 <=
    - David Carlisle - Wed, 5 Jul 2006 12:29:37 +0100
    - Mohsen Saboorian - Wed, 5 Jul 2006 15:22:06 +0330
    - David Carlisle - Wed, 5 Jul 2006 13:11:43 +0100
    - Michael Kay - Wed, 5 Jul 2006 13:01:32 +0100

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