Re: [xsl] XPath location problem

[Per Åberg <aberg.per@xxxxxxxx>]

Many thanks,  that was what I needed. :-)

//Pelle

----- Original Message -----
From: "Florent Georges" <darkman_spam@xxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, August 30, 2006 1:57 AM
Subject: Re: [xsl] XPath location problem


 You can use the following-sibling axis:

   > cat per.xml
   <animal>
     <species>
       <name language="English">Wolf</name>
       <name language="Spanish">Lobo</name>
       <name language="English">Warg</name>
       <name language="Latin">Canis Lupus</name>
       <name language="French">Loup</name>
     </species>
   </animal>

   > cat per.xsl
   <xsl:transform
       xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
       version="2.0">

     <xsl:output indent="yes"/>

     <xsl:template match="/">
       <xsl:apply-templates select="animal/species"/>
     </xsl:template>

     <xsl:template match="species">
       <xsl:variable name="second"
                     select="name[@language eq 'English'][2]"/>
       <new>
         <xsl:copy-of select="
             $second, $second/following-sibling::name"/>
       </new>
     </xsl:template>

   </xsl:transform>

   > gexslt per.xsl per.xml
   <?xml version="1.0" encoding="UTF-8"?>
   <new>
      <name language="English">Warg</name>
      <name language="Latin">Canis Lupus</name>
      <name language="French">Loup</name>
   </new>

 Regards,

--drkm

























p4.vert.ukl.yahoo.com uncompressed/chunked Tue Aug 29 23:13:38 GMT 2006


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