RE: [xsl] Element name Change for a node

[cknell@xxxxxxxxxx]

<xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>
<xsl:template match="address">
  <address>
    <xsl:apply-templates select="child::*[1]" />
  </address>
</xsl:template>

<xsl:template match="*[not(local-name() = 'address')][parent::*[local-name() = 'address']]">
  <xsl:variable name="elmnt-name">US_<xsl:value-of select="local-name()" /></xsl:variable>
  <xsl:element name="{$elmnt-name}">
    <xsl:value-of select="." />
  </xsl:element>
  <xsl:apply-templates select="following-sibling::*[1]" />
</xsl:template>
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Senthilkumaravelan Krishnanatham <senthil@xxxxxxxxx>
Sent:     Wed, 13 Sep 2006 18:00:01 -0700
To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  [xsl] Element  name Change for a node


Hi All,

I have the following structure in my XML and I want to transform this  
all "address" node content to prefix with "US".
Please let me how to create the XSL template for the given input.

Input
   <address>
    <streetAddress>123 First Street</streetAddress>
      <city>Sometown</city>
      <state>CA</state>
      <zip>12345</zip>
      <province />
      <country>USA</country>
   </address>

output
   <address>
    <US_streetAddress>123 First Street</US_streetAddress>
      <US_city>Sometown</US_city>
      <US_state>CA<US_/state>
      <US_zip>12345</US_zip>
      <US_province />
      <US_country>USA</US_country>
   </address>

I do not know how to create the XSL for it to transform.

Thanks for your help.


Regards,
Senthil