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Subject: Re: [xsl] Grouping the elements From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Thu, 14 Sep 2006 18:21:48 +0530 |
<xsl:template match="/Root">
<Root>
<xsl:for-each select="*[generate-id() =
generate-id(key('x', local-name())[1])]">
<xsl:choose>
<xsl:when test="count(key('x', local-name())) > 1">
<xsl:element name="{local-name()}List">
<xsl:copy-of select="key('x', local-name())" />
</xsl:element>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="key('x', local-name())" />
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</Root>
</xsl:template><?xml version="1.0" encoding="UTF-8"?> <Root> <year>2006</year> <year>2007</year> <year>2008</year> <week>1</week> <day>01</day> <day>02</day> </Root>
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<yearList>
<year>2006</year>
<year>2007</year>
<year>2008</year>
</yearList>
<week>1</week>
<dayList>
<day>01</day>
<day>02</day>
</dayList>
</Root>Hi,
I have the following xml for my input..
<?xml version="1.0" encoding="UTF-8"?> <Root> <year>2006</year> <year>2007</year> <year>2008</year> <week>1</week> <day>01</day> <day>02</day> </Root>
My expected output is
<Root> <yearList> <year>2006</year> <year>2007</year> <year>2008</year> <yearList> <week>1</week> <dayList> <day>01</day> <day>02</day> </dayList> </Root>
I want to group the element using xslt 1.0 and here element name is not fixed..it will be varied. when we have the same element then we need a parent element which have the element's name with List (i.e., yearList)
Is it possible to grouping in xslt1.0?
regards, raj
-- Regards, Mukul Gandhi
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